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amazon web services - Spark is inventing his own AWS secretKey

I'm trying to read a s3 bucket from Spark and up until today Spark always complain that the request return 403

hadoopConf = spark_context._jsc.hadoopConfiguration()
hadoopConf.set("fs.s3a.access.key", "ACCESSKEY")
hadoopConf.set("fs.s3a.secret.key", "SECRETKEY")
hadoopConf.set("fs.s3a.impl", "org.apache.hadoop.fs.s3a.S3AFileSystem")
logs = spark_context.textFile("s3a://mybucket/logs/*)

Spark was saying .... Invalid Access key [ACCESSKEY]

However with the same ACCESSKEY and SECRETKEY this was working with aws-cli

aws s3 ls mybucket/logs/

and in python boto3 this was working

resource = boto3.resource("s3", region_name="us-east-1")
resource.Object("mybucket", "logs/text.py") 
            .put(Body=open("text.py", "rb"),ContentType="text/x-py")

so my credentials ARE invalid and the problem is definitely something with Spark..

Today I decided to turn on the "DEBUG" log for the entire spark and to my suprise... Spark is NOT using the [SECRETKEY] I have provided but instead... add a random one???

17/03/08 10:40:04 DEBUG request: Sending Request: HEAD https://mybucket.s3.amazonaws.com / Headers: (Authorization: AWS ACCESSKEY:[RANDON-SECRET-KEY], User-Agent: aws-sdk-java/1.7.4 Mac_OS_X/10.11.6 Java_HotSpot(TM)_64-Bit_Server_VM/25.65-b01/1.8.0_65, Date: Wed, 08 Mar 2017 10:40:04 GMT, Content-Type: application/x-www-form-urlencoded; charset=utf-8, )

This is why it still return 403! Spark is not using the key I provide with fs.s3a.secret.key but instead invent a random one??

For the record I'm running this locally on my machine (OSX) with this command

spark-submit --packages com.amazonaws:aws-java-sdk-pom:1.11.98,org.apache.hadoop:hadoop-aws:2.7.3 test.py

Could some one enlighten me on this?

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1 Answer

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(updated as my original one was downvoted as clearly considered unacceptable)

The AWS auth protocol doesn't send your secret over the wire. It signs the message. That's why what you see isn't what you passed in.

For further information, please reread.


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