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Recent questions tagged 怎样理解连续使用的call()

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    function Foo() {} Foo.prototype.method = function(a, b, c) { console.log(this, a, b, c); }; Foo.method = function() { ... 和[...arguments].slice(1)两部分,并且把arguments[0]作为call方法的this值...
asked Jan 27, 2021 in Technique[技术] by 深蓝 (71.8m points)
0 votes
1.1k views
1 answer
    function Foo() {} Foo.prototype.method = function(a, b, c) { console.log(this, a, b, c); }; Foo.method = function() { ... 和[...arguments].slice(1)两部分,并且把arguments[0]作为call方法的this值...
asked Jan 27, 2021 in Technique[技术] by 深蓝 (71.8m points)
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