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macos - OSX app built with python quits immediately if app bundle is executed from finder but runs fine from command line

So I have this pyqt project and I want to build a osx.app dmg using pyinstaller

pyinstaller created the output in

dist/MyApplication.app

I can run it directly from terminal

cd dist
./MyApplication.app/Contents/MacOS/MyApplication

However, if I try to run the app bundle directly either with

open -a MyApplication.app

or

open .
# double click on MyApplication.app folder (appears just as MyApplication from finder)

It starts and then quits immediately

Now if I navigate to

$ cd ./Contents/MacOS/

and open a finder

$ open .
#then double click on MyApplication

it runs fine, but with a terminal windows opened in the background

Last login: Fri Mar 14 18:01:13 on ttys005
MyApplication/dist/MyApplication.app/Contents/MacOS/MyApplication ; exit;
MyApplication/dist/MyApplication.app/Contents/MacOS/MyApplication ; exit;

I use similar steps to build a windows exe without any issues (although there is no MyApplication.app concept in windows)

How do I diagnose this issue?

Thanks

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1 Answer

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by (71.8m points)

So I followed this py2app tutorial to see if it works better than pyinstaller, with this code

if __name__=="__main__":
    print "Hello"

and got similar results

i.e. app closes when I do

open -a HelloTest.app

while it runs fine with

./HelloTest.app/Contents/MacOS/HelloTest

but then this tidbit in the tutorial explains it

When run normally, your application’s stdout 
and stderr output will go to the Console logs. 
To see them, open the Console application:

$ open -a Console

After examining the console logs, it seems like if I run

open -a MyApplication.app

the app runs in a sandbox and if you open any file to write without specifying absolute path it will fail to create the file

if I run

./MyApplication.app/Contents/MacOS/MyApplication

directly the app can create files in the current directory

So I have to go back and specify the full path while creating files, instead of just assuming it will create in the working directory.


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