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为什么swagger json的生成的类，有的有discriminator字段，有的类没有这个字段，两个类的差别并不是很大？
    上图中的类没有discriminator，然后下图中的类却有这个字段，两个类的写法几乎一样，只是上图多了两个属性name和label，type属性都有必填校验，生成的json中必填校验也不一致 有前辈知道是为什么吗。 这对生成客户端代码来说很重要，图一中的类因为没有这个字段，继承自它的类都报错了...
asked Jan 27, 2021 in Technique[技术] by 深蓝 (71.8m points)
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